[Mp4-tech] [H.264]about the scaled versions of the motion vector in the 8.4.1.2.3 section

[JK Kim]

Hi Tan,

If all the roundings and clippings are omitted and a substation is made,

You can simply get the typical linear interpolation equation.

tx = ( 16 384 + Abs( td / 2 ) ) / td
(8-194)

    = 2^14 / td

 

DistScaleFactor = Clip3( -1024, 1023, ( tb * tx + 32 ) >> 6 )
(8-195)

                         = 2^8 * tb / td

 

mvL0 = ( DistScaleFactor * mvCol + 128 ) >> 8
(8-196)

          = (2^8 * tb / td * mvCol) >> 8

          = (tb / td) * mvCol

 

mvL1 = mvL0 - mvCol
(8-197)

          = (tb / td) * mvCol - mvCol

          = ((tb-td) / td) * mvCol

 

IMHO, (8-194)-(8-197) is designed to prevent overflow and reduce the number
of division.

Experts, please let me know if more!

 

                  JK

 

 

  _____  

From: mp4-tech-bounces lists.mpegif.org
[mailto:mp4-tech-bounces lists.mpegif.org] On Behalf Of Tan Rui -- Huawei
Sent: Monday, August 07, 2006 7:16 PM
To: mpeg 4 mail-list
Subject: [Mp4-tech] [H.264]about the scaled versions of the motion vector in
the 8.4.1.2.3 section

 

Hi, All experts,

 

I want to ask a question about the calculation about the scaled versions of
the motion vector in the 8.4.1.2.3 section.

I read lots of papers give the following equations:

 

mVL0 = (tb / td) * mvCol

mVL1 = ((tb - td) / td) * mvCol

 

But in the protocol 8.4.1.2.3 section, from the (8-194) equation to the
(8-199) equation, there is a DistScaleFactor 

variable. I can not calculate those equations from the above equations which
were found the papers. Can

some one provide some information about it? I spent some time to search the
detail description, but I can not

get any useful explanations.

 

Tan Rui

2006/8/8

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